345=-16t^2+28

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Solution for 345=-16t^2+28 equation: 



345=-16t^2+28

We move all terms to the left:

345-(-16t^2+28)=0

We get rid of parentheses

16t^2-28+345=0

We add all the numbers together, and all the variables

16t^2+317=0

a = 16; b = 0; c = +317;
Δ = b2-4ac
Δ = 02-4·16·317
Δ = -20288
Delta is less than zero, so there is no solution for the equation

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